has()关系的使用方法(更具可读性):
patients = Patient.query.filter(Patient.mother.has(phenoscore=10))
或加入(通常更快):
patients = Patient.query.join(Patient.mother, aliased=True) .filter_by(phenoscore=10)
has()关系的使用方法(更具可读性):
patients = Patient.query.filter(Patient.mother.has(phenoscore=10))
或加入(通常更快):
patients = Patient.query.join(Patient.mother, aliased=True) .filter_by(phenoscore=10)